Solving A. How Much Does Daytona Cost? in C++

By Md Shoriful Islam


A. How Much Does Daytona Cost?

Problem - A - Codeforces - Codeforces Round 900 (Div. 3)

Solving the Most Common Element Subsegment Problem in C++

Introduction: In the world of programming, problem-solving is a fundamental skill. It involves taking a complex task and breaking it down into smaller, manageable steps. In this blog post, we will dissect and solve a code problem that involves finding if a specific element exists in an array. The problem statement is as follows:

Problem Statement: You are given an array of integers and an integer K. The task is to determine whether K exists in the given array. You will be provided with multiple test cases, each containing an array and a value of K. For each test case, you need to output "YES" if K is found in the array and "NO" otherwise.

Solution: Let's break down the problem into steps and implement a solution in C++.Read the number of test cases (t) from input.
Enter a loop that runs t times, one iteration for each test case.
For each test case, read two integers, n and k, from input. n represents the number of elements in the array, and k is the value we want to find.
Declare an integer array named "arr" of size n to store the elements of the array.
Initialize a variable "d" to 0. This variable will be used to check if K is found in the array.
Enter a loop that runs n times, one iteration for each element in the array.
Read an integer from input and store it in arr[i].
Inside the loop, check if arr[i] is equal to k. If it is, set d to 1 to indicate that K has been found in the array.
After the loop, check the value of d.
If d is equal to 1, print "YES" to indicate that K exists in the array.
If d is not equal to 1, print "NO" to indicate that K does not exist in the array.
Repeat steps 3 to 11 for each test case.

Let's take a closer look at the code implementation:cpp

#include <iostream>
#include <vector>
#include <map>
 
 // mine solved
using namespace std;
 
int main() {
    int t;
    cin >> t;
   
    while (t--) {
        int n,k;
        cin>>n>>k;
        int arr[n];
        int d=0;
        for(int i=0; i<n; i++){
            cin>>arr[i];
            if(arr[i]==k) d=1;
        }
        if(d==1) cout<<"YES"<<endl;
        else cout<<"NO"<<endl;
       

    }
   
    return 0;
}


Conclusion: In this blog post, we have solved a code problem that involves finding whether a specific element exists in an array. We broke down the problem into smaller steps, implemented a solution in C++, and explained each part of the code. Problem-solving skills are essential in programming, and by dissecting and solving problems like this one, you can strengthen your coding abilities and become a more proficient programmer.

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